Centre of mass concepts, motion of COM, variable mass systems, collisions and conservation laws (JEE Main focus).

1) Centre of Mass (COM)

  • Centre of mass is a hypothetical point where the entire mass of a system can be assumed to be concentrated.
  • If all external forces act at COM, the system undergoes pure translation.
  • COM may lie inside or outside the body.
r_CM = (m₁r₁ + m₂r₂ + ... + mₙrₙ) / (m₁ + m₂ + ... + mₙ)
x_CM = (m₁x₁ + m₂x₂ + ... ) / (Total mass) y_CM = (m₁y₁ + m₂y₂ + ... ) / (Total mass)
Centre of mass lies closer to the heavier mass.

2) Centre of Mass of a Rigid Body

r_CM = ( ∫ r dm ) / ( ∫ dm )
x_CM = ( ∫ x dm ) / ( ∫ dm ) y_CM = ( ∫ y dm ) / ( ∫ dm )
  • If gravitational field is uniform, centre of mass = centre of gravity.

3) Motion of Centre of Mass

M r_CM = Σ mᵢ rᵢ M v_CM = Σ mᵢ vᵢ M a_CM = Σ F_ext
  • If ΣF_ext = 0, then COM velocity is constant.
  • If system is initially at rest and no external force acts, COM remains at rest.

4) Variable Mass System (Rocket Motion)

F_ext = dP/dt M dv/dt = F_ext + u (dM/dt)
Thrust force: F_thrust = u (dM/dt)
  • u = velocity of ejected mass relative to the rocket.
  • In rocket motion, weight can often be neglected compared to thrust.

5) Collision

  • Collision is a short-time interaction involving large mutual forces.
  • Total impulse on the system during collision is zero.
ΔP₁ + ΔP₂ = 0 ⇒ Total momentum conserved (if no external force)

6) Types of Collision

  • Elastic collision: Momentum and kinetic energy conserved.
  • Inelastic collision: Momentum conserved, KE not conserved.
  • Perfectly inelastic: Bodies stick together after collision.
Coefficient of restitution: e = (velocity of separation) / (velocity of approach) 0 ≤ e ≤ 1
  • e = 1 → perfectly elastic
  • e = 0 → perfectly inelastic

7) Head-on Elastic Collision (1D)

v₁f = [(m₁ − m₂)/(m₁ + m₂)] v₁i + [2m₂/(m₁ + m₂)] v₂i v₂f = [2m₁/(m₁ + m₂)] v₁i + [(m₂ − m₁)/(m₁ + m₂)] v₂i
  • If m₁ = m₂ → bodies exchange velocities.

8) Perfectly Inelastic Collision & Ballistic Pendulum

(m + M)v = mu v = (mu)/(M + m)
Fractional loss of KE: ΔK / K = M / (M + m)
  • Used in bullet–block (ballistic pendulum) problems.
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