Introduction
- Heights and distances problems use trigonometric ratios to find lengths that are not directly measurable.
- Assumption: The line of sight, horizontal line, and vertical objects form right-angled triangles.
Key Definitions
Angle of Elevation
- When an object is above the observer’s eye level.
- The angle between the line of sight and the horizontal through the observer.
Angle of Depression
- When an object is below the observer’s eye level.
- The angle between the horizontal and the line of sight, measured downward.
- Angle of elevation = Angle of depression (alternate interior angles).
Bearing
- Direction of an object measured from a fixed reference direction.
- Cardinal directions: North (N), South (S), East (E), West (W).
- Bearing is measured as the angle between the line of sight and a cardinal direction.
- Examples:
- NE = 45° from North towards East
- ENE = 22½° from East towards North
Standard Trigonometric Relations Used
- sin θ = (Perpendicular) / (Hypotenuse)
- cos θ = (Base) / (Hypotenuse)
- tan θ = (Perpendicular) / (Base)
- cot θ = 1 / tan θ
Problems Based on Dimensions
Two-Dimensional Problems
- All points lie in the same vertical plane.
- Directions shown using a vertical cross (N–S, E–W).
Three-Dimensional Problems
- Objects lie in different vertical planes.
- Directions represented using an oblique cross for the horizontal plane.
- Common in advanced JEE Main word problems.
Useful Results
- m–n Theorem: In a triangle, (m + n) cotθ = m cotα − n cotβ
- If DE ∥ AB in ΔABC, then AB / DE = BC / DC
Shadow Problems
- Shadow of an object depends on the position of the light source.
- Join the top of the object to the light source.
- Extend the projection on the horizontal plane to find shadow length.
Circle-Based Geometry Used in Heights & Distances
- Angles subtended by the same chord at the circumference are equal.
- If points A, B, P, Q are concyclic, then ∠APB = ∠AQB
- Angle between a tangent and a chord equals the angle in the alternate segment.
Important Geometry Theorems
- Apollonius Theorem: If AD is the median of ΔABC, then AB² + AC² = 2(AD² + BD²)
- Angle Bisector Theorem: If AD bisects ∠A, then BD / DC = AB / AC
- Power of a Point:
PA · PB = PT² (tangent case)
PA · PB = PC · PD (secant case)
JEE Main Tips
- Always draw a neat diagram before forming equations.
- Clearly mark angles of elevation/depression.
- Check whether the problem is 2D or 3D before solving.
- Bearings are frequently tested in integer-angle form (30°, 45°, 60°).
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Last modified: January 2, 2026
