Fundamental Principle of Counting
- Multiplication Principle: If one operation can be done in m ways and the next in n ways, then total ways = m × n.
- Addition Principle: If two operations are mutually exclusive and can be done in m and n ways, total ways = m + n.
Factorials
- n! = n × (n−1) × (n−2) × … × 1
- 0! = 1
Permutations
- Arrangement of objects where order matters.
- Permutations of n objects taken r at a time: ⁿPᵣ = n! / (n−r)!
- Permutations of n objects taken all at a time: nPn = n!
Permutations with Repetition
- When p objects are alike, q alike, r alike: n! / (p! q! r!)
- Permutations of n objects taken r at a time with repetition: nʳ
Permutations under Conditions
- r specified objects fixed at r places: (n−r)!
- m specified objects fixed at given places (m < r): ⁿ⁻ᵐPᵣ⁻ᵐ
- A particular object always included: r · ⁿ⁻¹Pᵣ⁻¹
- A particular object never included: ⁿ⁻¹Pᵣ
- m specified objects always together: m! × (n−m+1)!
- m specified objects never together: n! − m!(n−m+1)!
Circular Permutations
- Around a round table (clockwise ≠ anticlockwise): (n−1)!
- Necklace/garland (clockwise = anticlockwise): (n−1)! / 2
- Circular permutations of n objects taken r at a time:
- Clockwise ≠ anticlockwise: ⁿPᵣ / r
- Clockwise = anticlockwise: ⁿPᵣ / (2r)
Combinations
- Selection of objects where order does not matter.
- Combinations of n objects taken r at a time: ⁿCᵣ = n! / [r!(n−r)!]
- ⁿCᵣ = ⁿCₙ₋ᵣ
Combinations with Repetition
- Selections of r objects from n objects with repetition: ⁿ⁺ʳ⁻¹Cᵣ
Restricted Combinations
- k particular objects always included: ⁿ⁻ᵏCᵣ⁻ᵏ
- k particular objects never included: ⁿ⁻ᵏCᵣ
- Arrangements with k fixed objects: ⁿ⁻ᵏCᵣ⁻ᵏ × r!
Selections from Identical Objects
- Selections from n identical objects (r ≤ n): 1
- Selections from p alike and q alike objects: (p+1)(q+1) − 1
- Selections from p, q, r alike objects: (p+1)(q+1)(r+1) − 1
Division & Distribution
- Divide (m+n) distinct objects into groups of m and n: (m+n)! / (m!n!)
- Divide n identical objects among r persons:
- No restriction: ⁿ⁺ʳ⁻¹Cʳ⁻¹
- Each gets at least one: ⁿ⁻¹Cʳ⁻¹
Derangement
- Number of derangements of n objects: !n = n! (1 − 1/1! + 1/2! − 1/3! + …)
- Exactly r objects at correct positions: n! / r! × [1 − 1/1! + 1/2! − … + (−1)n−r / (n−r)!]
Important Results
- 1 + ⁿC₁ + ⁿC₂ + … + ⁿCₙ = 2ⁿ
- ⁿC₁ + ⁿC₂ + … + ⁿCₙ = 2ⁿ − 1
- Number of diagonals in n-gon: n(n−3)/2
- Exponent of prime p in n!: Eₚ(n!) = ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + …
JEE Main Focus Areas
- Circular permutations
- Derangements
- Distribution of identical objects
- Exponent of prime in factorial
- Restricted arrangements
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Last modified: January 2, 2026
